# Program name
PROJ = ce

# Compiler to be used
CC = gcc

# Flags for the compiler
CFLAGS = -Wall

INCLUDE = .
LIB	= .

ifdef NDEBUG
    OUT_DIR = release
else
    OUT_DIR = debug
    CFLAGS += -g -DDEBUG
endif

# Build list of object files
OBJ_LST = $(OUT_DIR)/fila.o \
	  $(OUT_DIR)/lista.o \
	  $(OUT_DIR)/pilha.o \
	  $(OUT_DIR)/ceui.o \
	  $(OUT_DIR)/log.o

proj_$(PROJ): $(OUT_DIR) $(OUT_DIR)/$(PROJ) Makefile

#*******
#* WARNING i have no idea why, but if you use the target name
#* to build a dir statically (as build_dir:) make does not
#* show the message "make: Nothing to be done for `target_name'."
#*****************************************************************
$(OUT_DIR):
	@if [ ! -e $(OUT_DIR) ]; then \
	    echo "Building dir '$(OUT_DIR)'..."; \
	    mkdir $(OUT_DIR); \
	    echo "done."; \
	fi

$(OUT_DIR)/$(PROJ): $(OBJ_LST)
	$(CC) -L$(LIB) -o $@ $(OBJ_LST) -lncurses
	@echo "done with '$(@)'";

$(OUT_DIR)/lista.o: lista.c lista.h mycommdef.h mydebug.h
	$(CC) -c $(CFLAGS) -I$(INCLUDE) -o $@ $<
$(OUT_DIR)/pilha.o: pilha.c pilha.h mycommdef.h mydebug.h
	$(CC) -c $(CFLAGS) -I$(INCLUDE) -o $@ $<
$(OUT_DIR)/fila.o: fila.c fila.h mycommdef.h mydebug.h
	$(CC) -c $(CFLAGS) -I$(INCLUDE) -o $@ $<
$(OUT_DIR)/ceui.o: ceui.c ceui.h mycommdef.h mydebug.h
	$(CC) -c $(CFLAGS) -I$(INCLUDE) -o $@ $<
$(OUT_DIR)/log.o: log.c log.h mycommdef.h mydebug.h
	$(CC) -c $(CFLAGS) -I$(INCLUDE) -o $@ $<

clean:
	-rm -f $(OUT_DIR)/*.o $(OUT_DIR)/$(PROJ) trab1-algii.tar.gz

cleanall:
	-rm -rf $(OUT_DIR) trab1-algii.tar.gz

dist: trab1-algii.tar.gz

trab1-algii.tar.gz:
	-tar czf trab1-algii.tar.gz *.h *.c Makefile scripts/